Subject: Re: [xsl] Joining sibling elements From: Marcin Miłkowski <milek_pl@xxxxx> Date: Thu, 11 Aug 2005 11:06:36 +0200 |
Best regards, Marcin
Given this XML - <?xml version="1.0" encoding="UTF-8"?> <root> <a><b>this</b><b>this 1</b><b>this 2</b></a> <a><b>this 3</b></a> <a><b>this 4</b><b>this 5</b></a> <a><b>this 6</b><b>this 7</b><b>this 8</b><b>this 9</b></a> <a><b>this 10</b><b>this 11</b><b>this 12</b><b>this 13</b></a> </root>
This XSLT stylesheet - <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:common="http://exslt.org/common" exclude-result-prefixes="common">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/root">
<root>
<xsl:apply-templates select="a"/>
</root> </xsl:template>
<xsl:template match="a"> <b> <xsl:variable name="rtf"><xsl:for-each select="b"><xsl:value-of select="."/><xsl:text> </xsl:text></xsl:for-each></xsl:variable> <xsl:value-of select="common:node-set($rtf)/text()"/> </b> </xsl:template> </xsl:stylesheet>
Produces following output - <?xml version="1.0" encoding="utf-8"?> <root> <b>this this 1 this 2 </b> <b>this 3 </b> <b>this 4 this 5 </b> <b>this 6 this 7 this 8 this 9 </b> <b>this 10 this 11 this 12 this 13 </b> </root>
Hope this helps,
Regards, Mukul
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