Re: [xsl] Problem with Sum function

[Jon Gorman <jonathan.gorman@xxxxxxxxx>]

I think I need a little alarm that beeps whenever one of my postings
gets longer than a page.  My last email might have been a little
confusing, and in my haste to get a reply off and get back to work I
might have let it run longer than I should have.  I apologize to all..

To summarize:

Your problem is essentially what I and the others guessed earlier.
You're using for-each loops and iterating through the whole set,
summing each node instead of summing values of multiple nodes.

Now, your example xml was a bit broken, and I'm just going to assume
that the server call takes care of calling the right Bnode.  If the I
take the example xml to be a somewhat accurate representation of your
paths, you should be able to do something like the below instead of
the current Bnode processing you have now.

<xsl:template name="Bnode">
  <xsl:variable name="sumNodes"
select="Bchild-nodes1/Bchild-node1[Bchild-node-num =
/root/nodes/node/child-nodes/child-node-num]"/>
  <xsl:value-of select="sum($sumNodes/Bchild-node-value)" />
</xsl:template>

This creates a node set of all the Bchild-node1 nodes that have a
node-num found in the root document's child-node-nums, based off the
path you had before.

It then simply gets the sum, without doing any calls to any other templates.


For that matter, I have a feeling that your server calls are a bit
more complex then needed as well.  However, I could imagine a system
where they would be cool to have.  Seeing as I have no idea what they
look like or how they work, can't tell you much in this vein though.

Of course, if you're also doing something else with your for-each
loops you can go ahead and do that separately from the sum.

Jon Gorman.