Re: [xsl] Roundtripability of identity transform

Subject: Re: [xsl] Roundtripability of identity transform
From: andrew welch <andrew.j.welch@xxxxxxxxx>
Date: Tue, 30 Aug 2005 12:37:17 +0100
On 30 Aug 2005 12:34:35 +0100, Colin Paul Adams
<colin@xxxxxxxxxxxxxxxxxx> wrote:
> >>>>> "Andrew" == andrew welch <andrew.j.welch@xxxxxxxxx> writes:
>     Andrew> Can it be assumed that the output of the transform:
>     Andrew> <xsl:template match="@*|*|node()"> <xsl:copy>
>     Andrew> <xsl:apply-templates select="@*|*|node()"/> </xsl:copy>
>     Andrew> </xsl:template>
>     Andrew> will be an exact copy of the input XML apart from:
>     Andrew> -The output will be minus the doctype -The output will
>     Andrew> contain any defaulted elements/attributes -All entities
>     Andrew> will be expanded -The output might be in different
>     Andrew> encoding (although I'm talking differences above the byte
>     Andrew> level here).
>     Andrew> Are there any other things to be aware of?
> Whitespace.

Hi Colin,

In what way would the whitespace differ?  Wouldn't the matching of
node() ensure all whitespace only text nodes are copied through?  (I'm
not using MSXML so all the nodes should be in the source)

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