Re: [xsl] concat all items in a sequence

[andrew welch <andrew.j.welch@xxxxxxxxx>]

> > I'm using the following:
> >
> > contains(elem, val)
> >
> > It's possible that 'elem' can be a sequence of more than one item.
> >
> > The way I've code around this is to use string-join with an empty
> > string as one of the arguments:
> >
> > contains(string-join(for $i in elem return $i, ''), val)
> >
> > Is there a better way?
>
> E.g.
>
>   some $i in elem satisfies contains($i, val)

Ahh yes, very nice, thanks Jarno.