Re: [xsl] concat all items in a sequence

Subject: Re: [xsl] concat all items in a sequence
From: andrew welch <andrew.j.welch@xxxxxxxxx>
Date: Tue, 30 Aug 2005 15:03:14 +0100
> > I'm using the following:
> >
> > contains(elem, val)
> >
> > It's possible that 'elem' can be a sequence of more than one item.
> >
> > The way I've code around this is to use string-join with an empty
> > string as one of the arguments:
> >
> > contains(string-join(for $i in elem return $i, ''), val)
> >
> > Is there a better way?
>
> E.g.
>
>   some $i in elem satisfies contains($i, val)

Ahh yes, very nice, thanks Jarno.

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