Subject: Re: [xsl] Sorting problem From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Wed, 31 Aug 2005 14:43:28 +0100 |
From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Sorting problem Date: Wed, 31 Aug 2005 12:49:18 +0100
me> No. keys are what you _do_ use in xslt 1 in this case. (in xslt2 you me> could use xsl:for-each-group)
Or rather you could use keys here, but in this case, i think you just want to sort don't you?
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" > <xsl:output method="xml" indent="yes"/>
<xsl:template match="root">
<root>
<xsl:for-each select="item">
<xsl:sort data-type="number" select="count(preceding-sibling::item[@type=current()/@type])"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
produces
$ saxon item.xml item.xsl <?xml version="1.0" encoding="utf-8"?> <root> <item type="A" subType="1"/> <item type="B" subType="2"/> <item type="D" subType="1"/> <item type="E" subType="2"/> <item type="A" subType="2"/> <item type="B" subType="3"/> <item type="D" subType="2"/> <item type="E" subType="4"/> <item type="A" subType="4"/> <item type="D" subType="3"/> <item type="D" subType="4"/> </root>
which appears to be what you wanted.
David
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