Re: [xsl] Sorting problem

Subject: Re: [xsl] Sorting problem
From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx>
Date: Wed, 31 Aug 2005 14:43:28 +0100

Very clever, turned my convoluted 40+ lines into half a dozen.



From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Sorting problem
Date: Wed, 31 Aug 2005 12:49:18 +0100

me> No. keys are what you _do_ use in xslt 1 in this case. (in xslt2 you
me> could use xsl:for-each-group)

Or rather you could use keys here, but in this case, i think you just want
to sort don't you?

<xsl:stylesheet xmlns:xsl=""; version="1.0" > <xsl:output method="xml" indent="yes"/>

<xsl:template match="root">

<xsl:for-each select="item">
<xsl:sort data-type="number" select="count(preceding-sibling::item[@type=current()/@type])"/>
<xsl:copy-of select="."/>



$ saxon item.xml item.xsl
<?xml version="1.0" encoding="utf-8"?>
   <item type="A" subType="1"/>
   <item type="B" subType="2"/>
   <item type="D" subType="1"/>
   <item type="E" subType="2"/>
   <item type="A" subType="2"/>
   <item type="B" subType="3"/>
   <item type="D" subType="2"/>
   <item type="E" subType="4"/>
   <item type="A" subType="4"/>
   <item type="D" subType="3"/>
   <item type="D" subType="4"/>

which appears to be what you wanted.


This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:

Current Thread