Subject: RE: [xsl] Extract First node|
From: "SINGH Navpreet" <Navpreet.SINGH@xxxxxxxxx>
Date: Fri, 2 Sep 2005 10:59:25 +1000
Made a mistake with attribute name, it is type not className in <xsl:value-of select="b/c[attribute::className='pdf']"/> -----Original Message----- From: SINGH Navpreet Sent: Friday, 2 September 2005 10:23 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Extract First node Hi I am having a problem with XPath expression for XSLT. I am trying to extract a node from xml with a special attribute. For example <a> <b> <c type="html">HTML file</c> </b> <b> <c type="text">Text File</c> </b> <b> <c type="pdf">First Pdf File</c> </b> <b> <c type="pdf">Second Pdf File</c> </b> <b> <c type="rtf">Rtf File</c> </b> </a> Element <c> can appear in any order and there could be a number of <c> with attribute type="pdf". I want to extract the first occurence of the element <c> which has a attribute type="pdf". I tried to extract it with <xsl:value-of select="b/c[attribute::className='pdf']"/> after matching the template for <a>. But I am getting "First Pdf File Second Pdf File". Can anyone tell me where I am making mistake. I am using Saxon-B8.5. Thanks Navpreet.