RE: [xsl] Moving an element to a new location in the Result-tree

Subject: RE: [xsl] Moving an element to a new location in the Result-tree
From: "Christopher R. Maden" <crism@xxxxxxxxx>
Date: Wed, 7 Sep 2005 18:39:44 -0700 (PDT)
Jim Graves wrote:
> Good ideas! More details to get closer to a solution. It's copying and
> maintaining the tree as it is, yet still not 'moving' (figuratively, not
> literally, since it's a new tree) the elements to the new location in
> the new (result) tree. I think I see your logic, but I'm still missing a
> crucial insight. Can you pinpoint what it is -- to see the result
> desired, below?

Your transformation is pretty good, but its output isnt well-formed.

> <xsl:template match="Transfer">
>     <xsl:apply-templates select="Person"/>
> </xsl:template>

That template causes the Transfer element to disappear; only its content
is output.

> <xsl:template match="Person">
>      <xsl:apply-templates select="*[not(self::OTHER_NAME)]"/>
>      <xsl:apply-templates select="OTHER_NAME"/>
> </xsl:template>

Similarly, this processes the contents of Person, but doesnt output a
Person element itself.  Note this in my sample transform:

<xsl:template match="document1">
    <xsl:apply-templates select="*[not(self::b1)]"/>
    <xsl:apply-templates select="b1"/>

The template for document1 creates a document222 element, and processes
its own children inside that result element.  You need something more like

<xsl:template match="Person">
     <xsl:apply-templates select="*[not(self::OTHER_NAME)]"/>
     <xsl:apply-templates select="OTHER_NAME"/>

Christopher R. Maden, Principal Consultant, crism consulting
<URL: >
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