Re: [xsl] Text Sort Problem

Subject: Re: [xsl] Text Sort Problem
From: "KrustyDerClown" <KrustyDerClown@xxxxxx>
Date: Sat, 10 Sep 2005 09:44:18 +0200

sorry for the late answer. My problem is not solved. Maybe i am too stupid.

There is also a little change in my problem. I sort not with data-type=number, but with the data-typ=text.

My code looks like this: (pb_number is not really a number. Its a number with a prefix like PB9999, therefore the sort with data-typ=text)

<xsl:for-each select="row">
<xsl:sort select="boolean(pb_number)" order="descending"/>
<xsl:sort select="pb_number" data-type="text"/>
<xsl:value-of select="string"/>


Entries with empty sequenz

So still the problem is that the entries with an empty sequenz as pb_number are shown first in the table.

Can anyone help again ?

Thank you for your support.

Greets Oliver

----- Original Message ----- From: "David Carlisle" <davidc@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, August 25, 2005 12:25 AM
Subject: Re: [xsl] Text Sort Problem

I have a similar problem (with data-type=number) a short time ago ... but
the solution at that time doesnt work here for this current problem.

the solution I posted (negating the sort key) doesn't work for non numeric keys, but the solution Mike posted (which was probably more sensible anyway) does work here. Just have an initial xsl:sort that is select="boolean(my_text)" as that will sort everything as either "true" or "false" depending on whether my_text selects any nodes. so you can then specify ascending or descending to control whether the empty case ("false") sorts before or after the non-empty case ("true")


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