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Subject: RE: [xsl] Traversing the tree From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sat, 10 Sep 2005 17:17:19 +0100 |
This kind of problem is best tackled using recursion. It's difficult to
write your first recursive stylesheet, but it's a very powerful technique to
have under your belt.
Basically you need to write a template that processes one of the siblings,
passing it the value of your "counter" or "running-total" as a parameter.
The template needs to make whatever changes are necessary to the counter or
running total, then make a recursive call to process the next element if
there is one, passing the new value of the counter or running total as a
parameter. When the final sibling is reached, you return (or write to the
output) the final value of the counter.
You can do this either with call-template or apply-templates (perhaps using
a special mode). I find it easier to use apply-templates, for two reasons:
(a) the current node is passed as an implicit parameter, and (b) the
recursion often terminates naturally when there are no more siblings.
Here's an example that totals @price*@qty over a set of sibling elements:
<xsl:template match="order">
<total-value>
<xsl:apply-template select="order-item[1]">
<xsl:with-param name="running-total" select="0"/>
</xsl:apply-templates>
</total-value>
</xsl:template>
<xsl:template match="order-item">
<xsl:param name="running-total"/>
<xsl:choose>
<xsl:when test="following-sibling::order-item">
<xsl:apply-template select="following-sibling::order-item[1]">
<xsl:with-param name="running-total" select="$running-total +
(@price*@qty)"/>
</xsl:apply-templates>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$running-total + (@price*@qty)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
I hope you can see how to adapt this technique to your problem.
Michael Kay
http://www.saxonica.com/
> -----Original Message-----
> From: Agnisys Technology (P) Ltd. [mailto:agnisys@xxxxxxxxx]
> Sent: 09 September 2005 21:31
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Traversing the tree
>
> David,
> My real problem is a little more complex as it turns out,
> and I'm stuck again!
> What if instead of using the count or sum functions, I need
> to use my own function for each of
> the nodes after the one with an "offset"? Can I still use
> some creative Xpath operation?
>
> For example:
> Input:
>
> <top>
> <a>
> <reg > A1 </reg>
> <reg offset="5" > A2 </reg>
> <reg > A3 </reg>
> <section>
> section_foo
> </section>
> <section>
> section_bar
> </section>
> <reg > A4 </reg>
> </a>
> </top>
>
> Assume there is a "sizeNode" function that returns a "size"
> of "section".
> sizeNode(section_foo) = 10
> sizeNode(section_bar) = 100
>
> So, the output of the above should be :
> A1 : 0
> A2 : 5
> A3 : 6
> section_foo : 7
> section_bar : 17
> A4 : 117
>
> So now I cannot use the following because the "size" of each
> "section" could be different.
> sum($x/@offset) +
> (count(preceding-sibling::reg|preceding-sibling::section) -
> count($x/preceding-sibling::reg|preceding-sibling::section))
>
> I need some way to add up "size"s of all the nodes after (and
> including) the node with an "offset"
> attribute.
>
> Once again I'm tempted to use a for loop and have a running
> counter, but I'm sure there is a
> better way.
>
> I would appreciate any help/pointer in this regard.
> Anupam.
>
> P.S: Jay thanks for your effort, for me it was more food for thought.
>
>
> --- "Agnisys Technology (P) Ltd." <agnisys@xxxxxxxxx> wrote:
>
> > David,
> > Your alternate strategy works well and solves the problem.
> > Although, I do need to study it carefully to understand
> how it is doing it!
> > Thanks,
> > Anupam.
> >
>
>
>
>
>
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