Re: [xsl] can't get xsl:sort to work

Subject: Re: [xsl] can't get xsl:sort to work
From: "Joris Gillis" <roac@xxxxxxxxxx>
Date: Mon, 19 Sep 2005 13:01:31 +0200
Tempore 12:58:08, die 09/19/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit UlyLee <ulyleeka@xxxxxxxxx>:

<xsl:for-each select="//complexarticle |
//simplearticle | //dummyarticle">
<xsl:sort select="@entry">
<tr valign="top">
<td><xsl:value-of select="@id"/></td>
<td><xsl:value-of select="@entry"/></td>
<td><xsl:variable name="x" select="count(.//xref)"/>
<xsl:for-each select=".//xref">
<xsl:value-of select="."/>
<xsl:if test="position() &lt; $x">

but when i run the transformation (i'm using
xmlspy) i get and error "Expected select attribute or
non empty content not both" but i have a select

The error message says it all. You need: <xsl:sort select="@entry"/> you don't have to encapsulate the whole loop with this element;-)

Joris Gillis (
Gaudiam omnibus traderat W3C, nec vana fides

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