Re: [xsl] How to select child elements of a given type

Subject: Re: [xsl] How to select child elements of a given type
From: Gustave Stresen-Reuter <tedmasterweb@xxxxxxx>
Date: Mon, 26 Sep 2005 19:40:22 +0100
THANK YOU!

You know, sometimes an extra set of eyes is really wonderful.

Ted

On Sep 26, 2005, at 7:42 PM, JBryant@xxxxxxxxx wrote:

<xsl:variable name="all">
<xsl:copy-of select="$path2pageAsSource | /root/folder"
/>
</xsl:variable>


produces a result tree fragment.

Try

<xsl:variable name="all" select="$path2pageAsSource | /root/folder"
/>


Just as a general rule, always write your variables this way, unless
circumstances force you to do otherwise.

Jay Bryant
Bryant Communication Services
(presently consulting at Synergistic Solution Technologies)




Gustave Stresen-Reuter <tedmasterweb@xxxxxxx> 09/26/2005 01:31 PM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx


To xsl-list@xxxxxxxxxxxxxxxxxxxxxx cc

Subject
[xsl] How to select child elements of a given type






<xsl:variable name="all">
<xsl:copy-of select="$path2pageAsSource | /root/folder"
/>
</xsl:variable>


         <xsl:for-each select="$all/descendant-or-self::folder">
             stuff...
         </xsl:for-each>

This for-each construct works with Saxon but not with Sablotron,
libxslt, or Xalan-J.

If I remove the /descendant-or-self::folder it works fine (but of
course, doesn't select the nodes I'm looking for).

I've tried using other shortcuts ($all//*/folder) and such, but they
all return the same error.

Any ideas what the problem might be?

Ted Stresen-Reuter

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