Re: [xsl] XSLT recursion problem

["M. David Peterson" <m.david.x2x2x@xxxxxxxxx>]

You can:

In XSLT 1.0 this:

<?xml version="1.0" encoding="UTF-8"?>
<ax:repeat xmlns:ax="uri:axnamespace">
    <sometag>
        <ax:items element="txt">
            <ax:item src="txt1.txt"/>
            <ax:item src="txt2.txt"/>
        </ax:items>
        <ax:items element="img">
            <ax:item src="img1.jpg"/>
            <ax:item src="img2.jpg"/>
        </ax:items>
    </sometag>
</ax:repeat>

Processed by this:


<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:ax="uri:axnamespace"
    version="1.0">
    <xsl:template match="/">
        <xsl:apply-templates select="ax:repeat/*" mode="initial"/>
    </xsl:template>
    <xsl:template match="*" mode="initial">
        <xsl:apply-templates select="*" mode="universal">
            <xsl:with-param name="name" select="name()"/>
        </xsl:apply-templates>
    </xsl:template>
    <xsl:template match="*" mode="universal">
        <xsl:param name="name"/>
        <xsl:variable name="position" select="position()"/>
        <xsl:element name="{$name}">
            <xsl:apply-templates select="../*/*[position() =
$position]" mode="parent">
                <xsl:with-param name="name" select="@element"/>
            </xsl:apply-templates>
        </xsl:element>
    </xsl:template>
    <xsl:template match="*" mode="parent">
        <xsl:param name="name"/>
        <xsl:param name="parentName"/>
        <xsl:element name="{$parentName}">
            <xsl:apply-templates select="." mode="child">
                <xsl:with-param name="name" select="$name"/>
            </xsl:apply-templates>
        </xsl:element>
    </xsl:template>
    <xsl:template match="*" mode="child">
        <xsl:param name="name"/>
        <xsl:element name="{$name}">
            <xsl:copy-of select="@*"/>
        </xsl:element>
    </xsl:template>
</xsl:stylesheet>

=

<?xml version="1.0" encoding="utf-8"?>
<sometag>
   <txt src="txt1.txt"/>
   <txt src="img1.jpg"/>
</sometag>
<sometag>
   <img src="txt2.txt"/>
   <img src="img2.jpg"/>
</sometag>

This relies on the idea the child count and the parent count being
exactly the same.  Theres a way to write so this isn't the case but if
we gave you all the answers you wouldnt have any fun :)

As such, have fun :)


On 9/28/05, Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> wrote:
> > The real problem is that I don't want to have to know anything about
> > <sometag>. That is, I would be free to use (and nest!) whatever
> > non-proprietary tag inside my <repeat>, without modifing it.
> > Probably there's no way in XSLT 1.0 (if it is, why creating tunnel in
> > 2.0 ;) , but if you see another solution...
> >
>
> Hi again Paolo,
>
> Why can you not have a general template for the "Sometag" and other
> elements that you just want to pass on?
>
> I think that your own solution would be able to provide, if you change
> the template that matches "Sometag" to the following:
>
> <xsl:template match="*">
>  <xsl:param name="index" select="1"/>
>  <xsl:copy>
>    <xsl:copy-of select="@*"/>
>    <xsl:apply-templates>
>      <xsl:with-param name="index" select="$index"/>
>    </xsl:apply-templates>
>    <!-- sometag content -->
>  </xsl:copy>
> </xsl:template>
>
> The match="ax:items" is more specific than match="*" and thus has
> higher priority.
>
> My solution, I think, you would have to change three templates:
>
> <xsl:template match="ax:repeat">
>  <xsl:apply-templates/> <!-- instead of <xsl:apply-templates
> select="sometag"/>-->
> </xsl:template>
>
> <xsl:template match="*"> <!-- Instead of <xsl:template match="sometag" -->
>   <xsl:copy> <!-- Copy element (shallow copy) -->
>     <xsl:copy-of select="@*"/> <!-- Copy all attributes -->
>      <!-- other non-proprietary elements to be processed: -->
>      <xsl:apply-templates select="*[not(self::ax:items)]"/>
>      <!-- Propriotary elements to be processed: -->
>      <xsl:apply-templates select="ax:items[1]" mode="first"/>
>   </xsl:copy>
> </xsl:template>
>
> And remove the <sometag> and </sometag>from the
> <xsl:template match="ax:items" mode="first">
> ..
> </
>
>
> Is this what you need?
>
> Regards,
> Ragulf Pickaxe :-)
>
>


--
<M:D/>

M. David Peterson
http://www.xsltblog.com