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Subject: Re: [xsl] (How) can I randomly access the result of a <xsl:for-each select="...? From: Ferdinand Soethe <xsl-list@xxxxxxxxxx> Date: Sat, 15 Oct 2005 09:09:50 +0200 |
Thanks everybody for your quick responses. I'm one major step closer
to my goals now.
Yet I seem to be missing something in this part if Michaels code:
> First, you put the result in a variable:
> <xsl:variable name="x">
> <xsl:for-each select=...
> <something/>
> </xsl:for-each>
> </xsl:variable>
Still XSLT 1.0:
If I do
<xsl:variable name="fragment" select="//ul"/>
(not using a for-each) everything works fine and I can cast the
variable to a nodeset and access it as documented.
However if I try
<xsl:variable name="fragment">
<xsl:for-each select="//ul">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
or
<xsl:variable name="fragment">
<xsl:for-each select="//ul">
<xsl:value-of select="."/>
</xsl:for-each>
</xsl:variable>
I only get a count() of 1 when transforming this test-document:
<?xml version="1.0" encoding="UTF-8"?>
<html>
<head></head>
<body>
<ul id="1">
<li id="11">Listenpunkt 11</li>
<li id="12">Listenpunkt 12</li>
<li id="13">Listenpunkt 13</li>
<li id="14">Listenpunkt 14</li>
</ul>
<ul id="2">
<li id="21">Listenpunkt 21</li>
<li id="22">Listenpunkt 22</li>
<li id="23">Listenpunkt 23</li>
<li id="24">Listenpunkt 24</li>
</ul>
<ul id="3">
<li id="31">Listenpunkt 31</li>
<li id="32">Listenpunkt 32</li>
<li id="33">Listenpunkt 33</li>
<li id="34">Listenpunkt 34</li>
</ul>
</body>
</html>
Any ideas what I got wrong here?
--
Ferdinand Soethe
(Btw: Xalan seems to also support the common:node-set function from
the xmlns:common="http://exslt.org/common"; namespace, so I used that
for portability)
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