Subject: RE: [xsl] removing nodes according to attibute value From: drkm <darkman_spam@xxxxxxxx> Date: Tue, 1 Nov 2005 22:31:45 +0100 (CET) |
Michael Kay: > Start with an identity template that copies everything: > <xsl:template match="*"> > <xsl:copy><xsl:copy-of > select="@*"/><xsl:apply-templates/></xsl:copy> > </xsl:template> Or matching "node()" if you want to copy everything, isn't it? <xsl:template match="node()"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> --drkm ___________________________________________________________________________ Appel audio GRATUIT partout dans le monde avec le nouveau Yahoo! Messenger Tilichargez cette version sur http://fr.messenger.yahoo.com
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