Subject: [xsl] Node ordering question with preceding axis From: Kenneth Stephen <marvin.the.cynical.robot@xxxxxxxxx> Date: Sat, 26 Nov 2005 19:42:44 -0600 |
Hi, I have the following testcase: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="xml" omit-xml-declaration="yes" /> <xsl:variable name="forest"> <tree>One</tree> <tree>Two</tree> <tree><tree>Three</tree></tree> <tree><tree>Four</tree><tree>Five</tree></tree> <tree><tree>Six</tree><tree>Seven</tree><tree>Eight</tree></tree> </xsl:variable> <xsl:template match="/"> <xsl:value-of select="$forest//tree[text() = 'Eight']/preceding::*" /> </xsl:template> </xsl:stylesheet> When run, this code produces: One Two Three Three FourFive Four Five Six Seven I'm not entirely clear about the expected behaviour of preceding axis with temporary trees, but I was expecting that the for the last "forest" of nodes, the node ordering would be "Seven" followed by "Six" since preceding is a reverse axis. What am I missing? Thanks, Kenneth
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