Re: [xsl] position

[Chandrasekhar A <chandrashekarrvt@xxxxxxxxx>]

Hello All,

         Sorry for the confusion. I want to find number of elments not tags.
 Thanks for input. I can find the number of element using count() function.
      But i didn't get understand, does this mean apply-templates call
return number of elements matched the select criteria?


Thanks and Regards,
Chandu

On 12/1/05, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> position() gives the position of a node in the current node list, which in
> this case is the set of nodes selected by the apply-templates call, which
is
> a list of length one, because you only selected the last one.
>
> xsl:number would probably suit your purpose better.
>
> You're not trying to count the number of tags, of course, but the number of
> elements. Most elements have two tags, a start tag and an end tag.
>
> Michael Kay
> http://www.saxonica.com/
>
> > -----Original Message-----
> > From: Chandrasekhar A [mailto:chandrashekarrvt@xxxxxxxxx]
> > Sent: 01 December 2005 06:47
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] position
> >
> > Hello,
> >
> >      I am trying to find number of tags in my xml using XSLT.
> > The XSLT is
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <xsl:stylesheet version="1.0"
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> > xmlns:fo="http://www.w3.org/1999/XSL/Format";>
> > <xsl:output method="text"/>
> >       <xsl:template match="/">
> >                       <xsl:apply-templates
> > select="dataroot/ReferenceTaskDb[last()]"/>
> >       </xsl:template>
> >       <xsl:template match="ReferenceTaskDb">
> >               <result> <xsl:value-of select="position()"/></result>
> >       </xsl:template>
> > </xsl:stylesheet>
> >
> >    It is returning 1. What is the wrong here ?
> >
> > Thanks and Regards,
> > Chandu