Subject: RE: [xsl] apply templates to all attributes except for one From: Tobi Reif <tobiasreif@xxxxxxxxxxxxx> Date: Sun, 8 Jan 2006 09:52:08 +0100 |
Hi Michael > In 2.0 you can write > > select="@* except @foo" Thanks, but for this project I'm confined to 1.0. > Or of course you can write > > <xsl:template match="@foo"/> > > with xsl:apply-templates select="@*" I'm not sure whether that applies to my case, here's the XSLT: <xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="para[@foo]"> <para> <xsl:apply-templates select="@*[not(local-name()='foo')]"/> <bar> <xsl:apply-templates select="@foo"/> </bar> <xsl:apply-templates select="node()"/> </para> </xsl:template> <xsl:template match="para/@foo"> <xsl:value-of select="."/> </xsl:template> </xsl:transform> Tobi > > -----Original Message----- [...] > > Hi > > > > In an XSLT I have the following: > > > > <xsl:apply-templates select="@*[not(local-name()='foo')]"/> > > > > It works. But is there a more elegant (or at least shorter) > > way to write this? > > > > Tobi
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