Subject: RE: [xsl] xml not well-formed From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sun, 8 Jan 2006 14:13:02 -0000 |
Use an attribute value template, id="{Location}" Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: dan@xxxxxxxxxxxxx [mailto:dan@xxxxxxxxxxxxx] > Sent: 08 January 2006 08:05 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] xml not well-formed > > In the below example, I would like to make the div id = <xsl:value-of > select="Location"/>, but this will not work since it is not > well-formed > xml. Is there any way to reference this node without using an > xml element? > > Thanks, > Dan > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:template match="/"> > <html> > <body> > <xsl:for-each select="songlist/song"> > <div id="<xsl:value-of select="Location"/>"><xsl:value-of > select="Name"/></div> > </xsl:for-each> > </body> > </html> > </xsl:template> > </xsl:stylesheet>
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