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Subject: Re: [xsl] should there be an error condition with XPATH function when param not defined? From: James Fuller <jim.fuller@xxxxxxxxxxxxxx> Date: Thu, 12 Jan 2006 14:01:57 +0100 |
Michael Kay wrote:
>>having some problems interpreting what is expected behavior with the
>>following XSLT.
>>
>>xml
>><test>1</test>
>>
>>xslt
>><xsl:template match="/">
>> <xsl:apply-templates select="."/>
>></xsl:template>
>>
>>
>
>That template rule will give you infinite recursion.
>
>
>><xsl:template match="test">
>> <xsl:value-of select="contains(test, $somevariable)"/>
>></xsl:template>
>>
>>
ya cut and paste error, should read
<xsl:value-of select="contains(., $somevariable)"/>
>>note that $somevariable has not been declared with either xsl:param or
>>xsl:variable.
>>
>>
>
>If $somevariable has not been declared, then you get a static error.
>
>
ok, not in firefox I am using though.
>>in http://www.w3.org/TR/xpath spec it is clear that the contains()
>>function should return a false condition and I cant find
>>anything to the
>>contrary that would say that this should throw an error (as
>>it doesnt in
>>Firefox XSLT processor).
>>
>>
>
>XPath 1.0 Section 3.1: A VariableReference evaluates to the value to which
>the variable name is bound in the set of variable bindings in the context.
>It is an error if the variable name is not bound to any value in the set of
>variable bindings in the expression context.
>
>
ahhh, read that and it bounced off my frontal lobe...thx for confirming
that this should be a static error.
cheers, Jim Fuller
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