Re: [xsl] Passing attributes in a node-set

[David Carlisle <davidc@xxxxxxxxx>]

> ..I want to have all values, 

then you want a node set of the attribute nodes. You can't do that by
copying the attribute nodes to a newly constructed root element as an
element can only hold one attribute with a given name, you want to just
select the attributes, so

<xsl:with-param name="value" select="//element/@avalue"/>

now if you use select= rather than using xsl:with-param with content
you generate a node set, which you can iterate over. I doubt you need to
use an explict integer parameter: the system will do the counting for
you, something like

...

<xsl:for-each select="$value">
 <xsl:variable name="name" select="."/>
 <xsl:for-each select="$value">
  <xsl:element name="{$name}_{position()}"><xsl:value-of select="."/>
 </xsl:for-each>
</xsl:for-each>


which will make

<foo_1>foo</foo_1>
<foo_2>bar</foo_2>
<bar_1>foo</bar_1>
<bar_2>bar</bar_2>


David

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