Subject: Re: [xsl] simple xslt question, retrieved data has no xml tags. From: omprakash.v@xxxxxxxxxxxxx Date: Mon, 23 Jan 2006 09:08:41 +0530 |
Hi, <xsl:apply-templates select="self" /> The above line in your xslt only selects the node for processing and without a corresponding template to match, it is left to the default templates to do something and they only output the text value of the nodes. If you'd like the xml structure add the following to your xslt. <xsl:template match="self"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> Hope this helps. cheers, prakash "Lizet Pena de Sola" To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> <lizet@ironsolut cc: (bcc: omprakash.v/Polaris) ions.com> Subject: [xsl] simple xslt question, retrieved data has no xml tags. 01/23/2006 08:49 AM Please respond to xsl-list Hello all, I need to import data from a 35MB xml file into a sql server database. I'm trying to cut that file in smaller chunks of data that can be more manageable. I'm using .NET framework 1.1 for this. I believe the processor is MSXML 4.0. I can't figure out what I'm doing wrong but each time I apply an xslt to the file I only get the text inside the nodes and I want to preserve the xml structure of the nodes I select, in order to create smaller xml files. Here's the code so far: Here's the xslt file <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns:xdt="http://www.w3.org/2005/xpath-datatypes"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" media-type="xml"/> <xsl:template match="//products[equipment/model='MX210']"> <xsl:apply-templates select="self" /> </xsl:template> </xsl:stylesheet> Dim doc2 As XmlDocument = New XmlDocument doc2.Load("DA880data.xml") ' Modify the XML file. Dim root As XmlElement = doc2.DocumentElement ' Create an XPathNavigator to use for the transform. Dim nav As XPathNavigator = root.CreateNavigator() ' Transform the file. Dim xslt As XslTransform = New XslTransform xslt.Load("transformdata.xsl") Dim writer As XmlTextWriter = New XmlTextWriter("output.xml", Nothing) xslt.Transform(nav, Nothing, writer, Nothing) Any idea is more than welcome. Thanks a lot for looking into this. Lizet This e-Mail may contain proprietary and confidential information and is sent for the intended recipient(s) only. If by an addressing or transmission error this mail has been misdirected to you, you are requested to delete this mail immediately. You are also hereby notified that any use, any form of reproduction, dissemination, copying, disclosure, modification, distribution and/or publication of this e-mail message, contents or its attachment other than by its intended recipient/s is strictly prohibited. Visit Us at http://www.polaris.co.in
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