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Subject: [xsl] Re: Transform XML to DXL using XSLT From: "rob Jackson" <robjackson2002@xxxxxxxxx> Date: Fri, 3 Mar 2006 01:18:28 -0800 |
Hi,
Thanks Gurus for your help.
I am really new to XSL so gets stuck in simple problems.
How can I modify the xsl program given by Michael and Florent if the
Document A is
<eapqp:ItemList>
<eapqp:Level>Level 1</eapqp:Level>
<eapqp:PartNumber>987654321</eapqp:PartNumber>
</eapqp:ItemList>
I tried by changing the xslt by
<xsl:template match="eapqp:Level">
<item name="Level"><text><xsl:value-of select="."/></item>
</xsl:template>
But it giving me error as illegal prefix.
Please suggest a solution.
Cheers,
Rob
On 3/2/06, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > Now I am stuck with a new problem and I am not able to find
> > any solution for it.
>
> If this is a new problem, then I wonder what problems you've been tackling
> until now. This is about as classic a one-to-one transformation as they
> come.
> >
> > I want to use XSLT to transform XML file to DXL (Domino XML) file. Dxl
> > file is also a xml file used by Lotus Notes.
> > For example what could be the xslt for converting document A
> > into document B.
>
> <xsl:template match="ItemList">
> <documents>
> <document>
> <xsl:apply-templates/>
> </document>
> </documents>
> </xsl:template>
>
> <xsl:template match="Level">
> <item name="Level"><text><xsl:value-of select="."/></item>
> </xsl:template>
>
> <xsl:template match="PartNumber">
> <item name="PartNumber"><text><xsl:value-of select="."/></item>
> </xsl:template>
>
> Michael Kay
> http://www.saxonica.com/
>
> >
> > Document A:
> >
> > <ItemList>
> > <Level>Level 1</Level>
> > <PartNumber>987654321</PartNumber>
> > </ItemList>
> >
> > Document B:
> >
> > <documents>
> > <document>
> > <item name="Level"><text>Level 1</text></item>
> > <item name="PartNumber"><text>987654321</text></item>
> > </document>
> > </documents>
> >
> > Thanks in advance.
> >
> > Cheers,
> > Rob
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