RE: [xsl] Determining the context node

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Hi,

At 06:23 AM 4/13/2006, Mike wrote:
> You can get the name of the context node using name(). Saxon has an
> extension function saxon:path() which gives you a full path to a node; I
> believe there are portable solutions to this problem at
>
> http://www.dpawson.co.uk/xsl/sect2/N6077.html
>
> but it seems to be down.

Here's some simple code to write an XPath for any element:

<xsl:template match="*" mode="make-path">
  <xsl:apply-templates select="ancestor-or-self::*" mode="make-step"/>
</xsl:template>

<xsl:template match="*" mode="make-step">
  <xsl:text>/</xsl:text>
  <xsl:value-of select="name()"/>
  <xsl:if test="(preceding-sibling::*|following-sibling::*)
                [name()=name(current())]">
    <xsl:text>[</xsl:text>
    <xsl:number/>
    <xsl:text>]</xsl:text>
  </xsl:if>
</xsl:template>

I leave it as an exercise how to extend this to handle attributes, 
the root, etc.

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
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