Re: [xsl] WordML Question and normalize-space() question

[David Carlisle <davidc@xxxxxxxxx>]

>  I'm wondering if it's possible to
> normalize all the space without removing the leading and trailing
> whitespace?

<xsl:variable name="x" select="normalize-space(concat('!',.,'!'))"/>
<xsl:value-of select="substring($x,2,string-length($x)-2)"/>


I didn't follow all your wordml but the following flattens out any b and
i elements (and can easily be extended any list of inline elements.

<p>
<b> bold <br/> text <i> bold and italic </i> just bold again </b>
plain text and images <img src="zzz"/>
</p>


gets turned into

 
<p>
<start-b/> bold <end-b/><br/><start-b/> text <end-b/><start-b/><start-i/> bold and italic <end-i/><end-b/><start-b/> just bold again <end-b/>
plain text and images <img src="zzz"/>
</p>

so all text is now a child of <p>.


<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
>
 
 
<xsl:template match="b|i">
  <xsl:apply-templates/>
</xsl:template>

<xsl:template match="text()">
  <xsl:for-each select="ancestor::*[self::b|self::i]">
   <xsl:element name="start-{name()}"/>
  </xsl:for-each>
  <xsl:value-of select="."/>
  <xsl:for-each select="ancestor::*[self::b|self::i]">
    <xsl:sort data-type="number" select="- position()"/>
   <xsl:element name="end-{name()}"/>
  </xsl:for-each>
</xsl:template>

<xsl:template match="*">
  <xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>
 </xsl:stylesheet>


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