[xsl] returning nodes (not a string) using variable-choose.

[Steve <subsume@xxxxxxxxx>]

The below somewhat elaborate lines assign a value to $typeInfo,
however they don't return results as a nodelist, just a big string.
------

<xsl:variable name="typeInfo">
	<xsl:choose>
		<xsl:when test="$type='Other'">
			<xsl:value-of select="$desc" />
		</xsl:when>
		<xsl:otherwise>
			<xsl:variable name="table">
				<xsl:choose>
					<xsl:when test="$type='Organizational Contact'">
						<xsl:text>CA_Orgs</xsl:text>
					</xsl:when>
					<xsl:when test="$type='Meeting or Training'">
						<xsl:text>CA_Meetings</xsl:text>
					</xsl:when>
					<xsl:when test="$type='Travel'">
						<xsl:text>CA_Travel</xsl:text>
					</xsl:when>
				</xsl:choose>
			</xsl:variable>
			<xsl:value-of
select="document(concat(concat(concat('http://server.org/getXML.asp?key=id&amp;val=',$desc),'&amp;table='),$table))"
/>
		</xsl:otherwise>
	</xsl:choose>
</xsl:variable>
<xsl:value-of select="$typeInfo" />
-----------------

Anyway to do this with XSLT 1.0 or am I pushing it?

--Steve