Re: [xsl] Having Trouble With Condition For Default Nodeset Selection

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

In your case, using the not() in the predicate
will be true for those members that are not the
value of the country code, therefore it will be
true for many members.  So, you need a predicate
that will only be true when the member is not found.

I think I would use something along the lines of:

<!--are you sure you need "//" in the following?-->
<xsl:variable name="codes"
              select="$currency-data//currency"/>
<xsl:variable name="found-code"
              select="$codes[@code = $country-code]"/>
<xsl:variable name="currency"
              select="$found-code |
                      $codes[@code='US'][not( $found-code )]"/>

I hope this helps.

. . . . . . . . . Ken

At 2006-07-05 09:57 +1000, Duncan Anker wrote:
> I am trying to look up a country code in a list
> of supported currencies, with a default to US if
> it is not found. I am using the XSLT 1.0 idiom of
>
> nodeset1[condition] | nodeset2[not(condition)]
>
> for a mutually exclusive result, however for the
> life of me I can't seem to find a suitable
> condition - I probably just need a figurative
> whack on the side of the head to help me "think
> different" (or should that be "differently?"). I
> have tried several different variations of the
> following with no luck, though I am probably
> just overlooking something really obvious:
>
> <xsl:variable name="currency"
> select="$currency-data//currency[@code=$country-code
> and @code != 'US'] |
> $currency-data//currency[not(@code=$country-code and @code != 'US')]" />
>
> Nothing seems to work no matter how I arrange
> that - the US currency is always unioned into
> the set. I'm sure that's the wrong condition to
> use, and there is something relatively simple I
> can add, but I'm just not seeing it.
>
> Does anyone have any suggestions, or perhaps a nerf mallet?

:{)}


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