Subject: [xsl] simulating for with foreach From: "Mohsen Saboorian" <mohsens@xxxxxxxxx> Date: Wed, 5 Jul 2006 14:06:17 +0330 |
Thanks Mike, Thanks David, to clarify my request, suppose I don't have needed sequence of nodes anywhere, and want to access every 4 elements: 1, 5, 9, ... to the end. Do I have to use <xsl:if test="position() mod 4 = 1", or there is a more flexible way?
> but there are situations in which you can not use > position() because it doesn't give you the exact node (for example > when you have #text elements randomly beside <node>.
If you only want to iterate over elements, just select elements not text nodes, then position() will give the position in the sequence of selected items.
<xsl:for-each seelct="node[position() mod 2 =1]"
does what you want, I think.
David
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] simulating for with forea, David Carlisle | Thread | Re: [xsl] simulating for with forea, David Carlisle |
Re: [xsl] simulating for with forea, David Carlisle | Date | Re: [xsl] simulating for with forea, David Carlisle |
Month |