Re: [xsl] simulating for with foreach

["Mohsen Saboorian" <mohsens@xxxxxxxxx>]

Thank you very much. That fully solved my problem, but just for my
curiosity, why position() (and also last()) do return sequential
numbers instead of real positions. I mean position() returns 1, 2, 3
instead of 1, 4, 9...

Thanks.

> Well as I said in my reply, normally you _want_ position() to go in that
> sequence so you can number the output, check for the last item using
> position()=last() etc.
>
> So either you keep position() that way and just calculate the old
> position by inverting the formula, (position()-1)*4+1 in this case
> or you do as you originally did and select them all and use xsl:if just
> to process teh opnes you want.
>
> <xsl:for-each select="nodes">
> <xsl:if test="position() mod 4 = 1">
>  ...
>
> then inside the xsl:if position() will be 1,5,...
>
> really I'm not sure what the problem is that you are having, since it
> seems like the final preferred answer is the code you started with?
>
> David