Subject: Re: [xsl] XSLT to remove characters and whitespaces From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Fri, 07 Jul 2006 11:08:41 -0400 |
<greeting> <to>Georg</to> <from>XSL-List</from> <text>Hey, how are tricks?</text> </greeting>
<greeting>GeorgXSL-ListHey, how are tricks? <to>Georg</to> <from>XSL-List</from> <text>Hey, how are tricks?</text> </greeting>
<xsl:template match="text()"/> <xsl:value-of select="normalize-space()"/> </xsl:template>
<xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template>
Cheers, Wendell
Hello,
i have a xml file with some content in it which contains some unwanted carriage returns and whitespaces. Now I'm trying to write a stylesheet which makes an exact copy of the source file but without the returns and whitespaces. I thought this should work:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output name="stripped" method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:result-document format="stripped" href="result.xml">
<xsl:apply-templates/>
</xsl:result-document>
</xsl:template>
<xsl:template match="*">
<xsl:element name="{name()}">
<xsl:value-of select="normalize-space(translate(translate(.,
'
', ' '), '	', ' '))"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
But the output is a mess in parts. What am I doing wrong?
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