Re: [xsl] Fwd: Combing two different documents

["Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>]

Taking hint from Andrew's answer, I think you need a stylesheet
something like this:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="xml" indent="yes" />

<xsl:variable name="doc2" select="document('file2.xml')" />

<xsl:template match="node() | @*">
  <xsl:copy>
    <xsl:apply-templates select="node() | @*" />
  </xsl:copy>
</xsl:template>

<xsl:template match="*[not(*)]">
  <xsl:copy-of select="." />
  <xsl:copy-of select="$doc2//*[not(*)]" />
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

On 7/17/06, David B <daavidb@xxxxxxxxx> wrote:
> Hello,
>
> I am trying to combine to seperate XML documents that have the same
> structure but different leaf nodes, e.g:
> ---File 1.xml---
> <base>
>     <foo>
>          <bar1>123</bar1>
>     </foo>
> </base>
> --File 2.xml----
> <base>
>     <foo>
>         <bar2>abc</bar2>
>     </foo>
> </base>
>
> I want the output to be:
> <base>
>     <foo>
>         <bar1>123</bar1>
>         <bar2>abc</bar2>
>     </foo>
> </base>
>
> Preferably without hardcoding too much of the structure of the file
> into the .xsl.
>
> I thought I would run an xslt on file1, and then use the XSLTSL
> xpath:node template to get the xpath of the current node, construct a
> string like:
>        <xsl:variable name="path2">
>            <xsl:text>document('file1.xml')/</xsl:text>
>            <xsl:value-of select="$path"/>
>            <xsl:text>bar2</xsl:text>
>        </xsl:variable>
>
> And then get the contents of the element that xpath points to using:
> <xsl:value-of select="$path2'"/>
>
> But that just prints the contents of the variable $path2! I would like
> to use evaluate($path2) but that's not in the xslt standard, so is
> there any other way of achieving what I am trying to achieve?
>
> /David