RE: [xsl] Assigning multiple xml's file names into variable name using for-each possible?

["Michael Kay" <mike@xxxxxxxxxxxx>]

> So, what I was trying to do is to make a seperate xml file 
> listing all the xml file to be processed. e.g: xmlFileList.xml 
> 
> 	<ContentGroup name="Arts">
> 		<ContentFile>S207.xml</ContentFile>
> 		<ContentFile>S103_2.xml</ContentFile>
> 		<ContentFile>DD03.xml</ContentFile>
> 		.... etc etc
> 	</ContentGroup>
> 
> 
> And in the xsl file, trying to loop thro to get each file 
> name and process it like:
> 
> <xsl:template match="/"> <!-- of xmlFileList.xml -->
> 	<xsl:for-each select="//ContentFile">
> 		<xsl:variable name="fileName" select="node()"/>
> 		<xsl:variable name="currentFile" 
> select="document('{$fileName}')"/>
> 

You just want

select="document($fileName)"

Curly braces are only used when an XPath expression is embedded in attribute
text, never to embed one XPath expression inside another.

Michael Kay
http://www.saxonica.com/