Re: [xsl] Recursive counting

[Steve <subsume@xxxxxxxxx>]

Much appreciated, but I'm still on the 1.0 train. Havin' trouble using
DLLs for Saxon.NET without going Visual Studio crazy. =)

Thanks tho,

-S

On 7/19/06, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > Well after success with my first recursive template I was all
> > set to make one of my own, but now shamefully am coming to
> > the list for advice over something that appears quite simple.
>
> First thing is to recognize this as a grouping problem. For each distinct
> value of @type you need to do something.
>
> In XSLT 2.0:
>
> <xsl:for-each-group select="/*/options/o" group-by="@type">
>   <xsl:sort select="current-grouping-key()"/>
>   <out type="{current-grouping-key()}"
>        count="{count(/*/person[@pref=current-group()]}"/>
> </xsl:for-each-group>
>
> >
> > XML ------->
> >
> > <options>
> >    <o type="A">who</o>
> >    <o type="A">what</o>
> >    <o type="A">when</o>
> >    <o type="B">how</o>
> >    <o type="B">nexus</o>
> >    <o type="B">triumph</o>
> >    <o type="C">alligator</o>
> >    <o type="C">spurn</o>
> > </option>
> >
> > <people>
> >   <person pref="who" />
> >   <person pref="nexus" />
> >   <person pref="how" />
> >   <person pref="alligator" />
> >   <person pref="spurn" />
> >   <person pref="triumph" />
> >      .... etc ....
> > </people>
> >
> >
> > Desired output ------->
> >
> > <!-- @count corresponds to number of times  the preference
> > appeared among the list of <people> --->
> >
> >   <out type="A" count="1" />
> >   <out type="B" count="3" />
> >   <out type="C" count="1" />
> >
> >
> > Stipulation: --------->
> >
> > <out>'s must be sorted alphabetically, regardless of <option> order.