Re: [xsl] Getting the current node, in a different document

["andrew welch" <andrew.j.welch@xxxxxxxxx>]

On 7/19/06, David B <daavidb@xxxxxxxxx> wrote:
> Hello,
>
> I have two different documents, file1.xml and file2.xml, with similar
> structure but different leaf nodes. I would like to do something like:
>
> <xsl:for-each select="*[type='bar']">
>     value 1: <xsl:value-of select="id">
>     value 2: <xsl:value-of
> select="document('file2.xml')/$current_xpath_in_file1/description">
> </xsl:for-each>
>
> But that is obviously not a valid xpath! How could a acheive the same
> result using actualt xslt?

If you don't mind using extensions you could use a combination of
saxon:evaluate() and saxon:path()

cheers
andrew