Subject: [xsl] Problem passing parameter ASP -> XSL From: "Garry Searle" <garry@xxxxxxxxxxxxxxxxxx> Date: Tue, 25 Jul 2006 21:42:28 +0930 |
Hi I'm putting together my first xml-xsl together and have just one problem. I cant seem to get a parameter to work. I'm wanting to pass the parameter from an .ASP page. I am calling this page with: showStage.asp?paramVal1=test¶mVal2=12 and the full ASP and XSL documents are below. I set a default paramter which displays, but the passed parameter is blank. I'd appreciate any feedback. Thanks Garry SHOWSTAGE.ASP ============= <%@ LANGUAGE="VBSCRIPT" %> <% option explicit %> <% Response.Buffer=True %> <% Dim objXML, objXSL, xslTemplate, xslProc, paramVal1, paramVal2 set objXML = Server.CreateObject("MSXML2.FreeThreadedDOMDocument") objXML.async = false objXML.load(Server.MapPath("StageInfo.xml")) set objXSL = Server.CreateObject("MSXML2.FreeThreadedDOMDocument") objXSL.async = false objXSL.load(Server.MapPath("Stage.xsl")) set xslTemplate = Server.CreateObject("MSXML2.XSLTemplate") xslTemplate.stylesheet = objXSL set xslProc = xslTemplate.createProcessor() paramVal1 = Request.querystring("paramVal1") if paramVal1 <> "" then xslProc.addParameter "paramVal1", paramVal1 end if paramVal2 = Request.querystring("paramVal2") if paramVal2 <> "" then xslProc.addParameter "paramVal2", paramVal2 end if xslProc.input = objXML xslProc.transform() Response.Write(xslProc.output) %> STAGE.XSL ========= <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:param name="paramVal1" select="'default 1'"/> <xsl:param name="paramVal2" /> <html> <body> <xsl:value-of select="$paramVal1" /> <----- shows "default 1" <xsl:value-of select="$paramVal2" /> <----- doesn't show anything </body> </html> </xsl:template> </xsl:stylesheet>
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