Subject: Re: [xsl] $variables with xsl:key() From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Tue, 25 Jul 2006 11:52:41 -0400 |
Regards, Wendell
The below represents my attempts to create a table which looks something like
Cognitive --- 26 Hearing --- 17 *type3* --- X
X = times which a disability of type=type3 appears in $vP2/Records/Record as disabPrimary
My understanding of key breaks down somewhere. If you see what I am doing wrong, please let me know.
Thanks,
-Steve
------------------------------------------------------- XSL version = 1.0
XSL------------
<xsl:template match="/" >
<xsl:apply-templates select="document('../../Consumer.xml')/disabilities" />
<table>
<xsl:for-each select="document('../../Consumer.xml')/disabilities/option[generate-id(.)=generate-id(key('options',@type)[1])]">
<xsl:sort select="@type"/>
<xsl:apply-templates mode="x" select="$vP2/Records">
<xsl:with-param name="type" select="@type" />
</xsl:apply-templates>
</xsl:for-each>
</table>
</xsl:template>
<xsl:template match="Records" mode="x"> <xsl:param name="type" /> <tr> <td> <xsl:value-of select="$type" /> </td> <td> <xsl:value-of select="count(key('oldID',Record))" /> </td> </tr> </xsl:template>
Variable $vP2 contains via document()-----------
<Records> <Record> <disabPrimary>101</disabPrimary> </Record> <Record> <disabPrimary>201</disabPrimary> </Record> <Record> <disabPrimary>151</disabPrimary> </Record>
.....etc
And consumer.xml disabilties are like----------
<option oldID="413" type="Physical" name="Cancer"/> <option oldID="400" type="Cognitive" name="Cerebral Palsy"/> <option oldID="410" type="Physical" name="Chronic Fatigue Syndrome"/> <option oldID="305" type="Cognitive" name="Cognitive-Other"/>
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