[xsl] how to define stylesheet for the XML with href

Subject: [xsl] how to define stylesheet for the XML with href
From: "dhavalkumar thakker" <dhavalkumar@xxxxxxxxxx>
Date: Fri, 28 Jul 2006 14:58:04 +0100
Hi all,

I have a XML file ( infect, its a SOAP response recieved from a Web
service), i want to define stylesheet for this file(response). The file
is:


<?xml version="1.0" encoding="utf-8"?>

<soapenv:Envelope
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/";
xmlns:xsd="http://www.w3.org/2001/XMLSchema";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>

	<soapenv:Body>
		<ns1:getQuotationResponse
soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/";
xmlns:ns1="http://WizzAir";>
			<getQuotationReturn href="#id0"/>
		</ns1:getQuotationResponse>

		<multiRef id="id0" soapenc:root="0"
soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/";
xsi:type="ns2:Price" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/";
xmlns:ns2="http://WizzAir";>

			<amount xsi:type="xsd:double">100.0</amount>
			<currency xsi:type="xsd:string">GBP</currency>
		</multiRef>
	</soapenv:Body>
</soapenv:Envelope>


I have defined the XSLT as follows(omitted some parts for simplicity):

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
	<xsl:template match="/getQuotationReturn">
			<xsl:variable name="X2" select="amount"/>
			<xsl:variable name="X1" select="currency"/>

                        <xsl:value-of select="$X2"/>

			<xsl:value-of select="$X1"/>



However, when i open the file, the value of both (X2 and X1 is
empty)...any suggestions??


Thanks..
--
Dhavalkumar Thakker
Phd candidate,
Semantic Web Services Research Group,
Nottingham Trent University, England
http://clarinet.doc.ntu.ac.uk:2000/dysec/dthakker.html

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