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Subject: RE: [xsl] Document function (was Getting an error with a variable) From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sat, 29 Jul 2006 10:26:31 +0100 |
> This is a snippet of code. Am I on the right
> track or is there a more efficient way?
>
> <xsl:for-each
> select="/legs/competition/leg/Competitor[../../@name=$paramVal1]">
> <tr>
> <td><xsl:value-of select="@no"/></td>
> <xsl:variable name="cNum">
> <xsl:value-of select="@no"/>
> </xsl:variable>
Never do this. Write
<xsl:variable name="cNum" select="@no"/>
There's no need to construct a new result tree fragment when you only want a
reference to a node. (And no need for three lines of code when one would do
- XSLT is verbose enough without making it worse).
> <td><xsl:value-of
> select="document('EntryList.xml')/entrylist/competition/entry/
> @driverSurname
> [../@no=$cNum]"/>
> <td><xsl:value-of
> select="document('EntryList.xml')/entrylist/competition/entry/
> @coDriverSurna
> me[../@no=$cNum]"/>
You're less reliant on the optimizer if you define a variable:
<xsl:variable name="entry"
select="document('EntryList.xml')/entrylist/competition/entry[@no=$cNum]"/>
then select="$entry/@driverSurname" and select="$entry/@codriverSurname"
Note also, predicates can appear on steps in a path expression other than
the last. You can write
document('EntryList.xml')/entrylist/competition/entry[@no=$cNum]/@driverSurn
ame
Michael Kay
http://www.saxonica.com/
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