Re: [xsl] populating table with sorted elements

["andrew welch" <andrew.j.welch@xxxxxxxxx>]

On 7/29/06, Christian Marc Schmidt <christianmarc@xxxxxxxxx> wrote:
> I am a newcomer to XML/XSLT and am struggling
> with a bit of code in which I am attempting to populate
> a six-column table, while allowing an xsl:sort.
>
> Here is a section of my current code:
>
> <?xml version="1.0" encoding="utf-8"?>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
> ...
>
> <table width="970" border="0" cellspacing="0" cellpadding="0">
>     <xsl:for-each select="xml/work/*[position() mod 6 = 1]">
>         <tr>
>             <xsl:apply-templates
> select=".|following-sibling::*[position() &lt; 6]" />
>         </tr>
>     </xsl:for-each>
> </table>
>
> ...
>
> The XML structure I've set up looks like this:
>
> <xml>
>     <work>
>         <piece>
>         </piece>
>          <piece>
>         </piece>
>         ...
>     </work>
> </xml>
>
> How would I go about adding sort functionality? It seems like it would
> be easy enough, yet all of my attempts so far have failed...
>
> Any suggestions would be much appreciated!

<xsl:sort> can be a child of <xsl:apply-templates>, eg:

<xsl:apply-templates select="........">
 <xsl:sort select="....."/>
</xsl:apply-templates/>

cheers
andrew