RE: [xsl] Occurences of comma-separated values

["Michael Kay" <mike@xxxxxxxxxxxx>]

Your problem breaks into two halves: (a) tokenizing, and (b) grouping.

Both steps are much easier with XSLT 2.0 than 1.0. In 2.0 it's simply

<xsl:for-each-group select="list/*/@ids/tokenize(.,',')" group-by="."/>
  <xsl:sort select="current-grouping-key()"/>
  <xsl:value-of select="current-grouping-key()"/>
  <xsl:text>: </xsl:text>
  <xsl:value-of select="count(current-group())"/>
</xsl:for-each-group>

For XSLT 1.0 you can learn about tokenizing by looking at the string
functions/templates at www.exslt.org, and you can learn about grouping at
www.jenitennison.com/xslt/grouping

Michael Kay
http://www.saxonica.com/



> -----Original Message-----
> From: Smoother@xxxxxx [mailto:Smoother@xxxxxx]
> Sent: 29 July 2006 15:08
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Occurences of comma-separated values
>
> For instance, I have the following XML-File:
>
> <list>
>   <item1 ids="a,b,c,e" />
>   <item2 ids="b,c,d" />
>   <item3 ids="a,c,d,e" />
>   <item4 ids="e,f" />
>   <item5 ids="a,c,d,e,g" />
> </list>
>
> I contemplate how to count the occurences of
> (a) all ids (e.g. 'a') in the document and
> (b) to count the occurences of a specific (known) id (e.g.
> 'f') in the document.
>
> For case a the output should be like this:
>
> a: 3
> b: 2
> c: 4
> d: 3
> e: 4
> f: 1
> g: 1
>
> I started to learn XSL yesterday. For several other problems,
> I found an easily adaptable solution on the web, numerous
> time on this list here.
> But for my current problem, there was no such help available.
> Of course, I found here a similar posting which deals with
> occurences of equal nodes
> (http://www.stylusstudio.com/xsllist/200309/post20830.html),
> but I don't know how to adapt it. So please find a solution
> and help me and others who have the same problem.
>
>
> Thanks in advance,
>
> S. Renault
> --
>
>
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