RE: [xsl] Make RSS output?

Hi,

Yopu specified "text" as your desired output format, which doesn't seem to be
what you wanted.
Change

<xsl:output method="text" doctype-public="-//Netscape
Communications//DTD RSS 0.91//EN"
doctype-System="http://my.netscape.com/publish/formats/rss-0.91.dtd";
encoding="utf-8" />

to

<xsl:output method="xml" doctype-public="-//Netscape
Communications//DTD RSS 0.91//EN"
doctype-System="http://my.netscape.com/publish/formats/rss-0.91.dtd";
encoding="utf-8" />

and you get it.

best regards,
Roman

> -----Original Message-----
> From: Smoother@xxxxxx [mailto:Smoother@xxxxxx]
> Sent: Monday, July 31, 2006 2:39 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Make RSS output?
>
> Hi,
>
> today I have tried to output rss with xsl. I'm using libxslt
> (which is used by php5) to do so, but I always get
> well-formatted html.
>
> My stylesheet:
> =====================================================
>
> <?xml version='1.0' encoding='utf-8'?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>                 xmlns:rss="http://purl.org/rss/1.0/";
>                 xmlns:dc="http://purl.org/dc/elements/1.1/";
>
> xmlns:content="http://purl.org/rss/1.0/modules/content/";
> version="1.0">
>
>     <xsl:output method="text" doctype-public="-//Netscape
> Communications//DTD RSS 0.91//EN"
>
> doctype-system="http://my.netscape.com/publish/formats/rss-0.9
> 1.dtd" encoding="utf-8" />
>
>     <xsl:template match="/">
>
>         <rss version="0.91">
>             <channel>
>                 <title>...</title>
>                 <link>...</link>
>                 <description>...</description>
>                 <language>en-us</language>
>
>                 <copyright>...</copyright>
>
>                 <item>
>                     <title>...</title>
>                     <description>...</description>
>                     <link>...</link>
>                 </item>
>             </channel>
>         </rss>
>
>     </xsl:template>
>
> </xsl:stylesheet>
>
>
> Output:
> =====================================================
>
> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
>     "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
> <html xmlns="http://www.w3.org/1999/xhtml";>
>   <head>
>     <title></title>
>   </head>
>   <body>
>     .........en-us............
>   </body>
> </html>
>
>
> It should be something like this:
> =====================================================
>
> <?xml version="1.0" encoding="ISO-8859-1" ?>
> 	<!DOCTYPE rss PUBLIC "-//Netscape Communications//DTD
> RSS 0.91//EN" "http://my.netscape.com/publish/formats/rss-0.91.dtd";>
> 	<rss version="0.91">
> 	<channel>
> 		<title>...</title>
> 		<link>...</link>
> 		<description>...</description>
> 		<language>en-us</language>
>
> 		<copyright>...</copyright>
>
> 			<item>
>
> 				<title>...</title>
> 				<description>...</description>
> 				<link>...</link>
> 			</item>
>
> 	</channel>
> 	</rss>
>
>
> As I said, I'm using php5 with xsltProcessor and DomDocument,
> the same way as it is used in the example found at
> http://de2.php.net/manual/en/function.xsl-xsltprocessor-construct.php
>
>
> What is necessary to get there? Can someone please give an
> example? Google returns only tuotrials on how to access rss with xsl.
>
> Thanks, S. Renault.
> --
>
>
> Echte DSL-Flatrate dauerhaft f|r 0,- Euro*. Nur noch kurze Zeit!
> "Feel free" mit GMX DSL: http://www.gmx.net/de/go/dsl
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