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Subject: Re: [xsl] Using XPath to match two node levels with the same name From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Mon, 7 Aug 2006 21:10:09 +0530 |
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
<xsl:template match="/"> <xsl:apply-templates select="topic" /> <xsl:apply-templates select="//topic[count(ancestor::topic) = 1]" /> </xsl:template>
<xsl:template match="topic">
<xsl:variable name="filename" select="concat(@id,'.xml')"/>
<redirect:write select="$filename">
<topic>
<xsl:copy-of select="@*" />
<xsl:apply-templates mode="x"/>
</topic>
</redirect:write>
</xsl:template><xsl:template match="topic[count(ancestor::topic) = 1]"> <xsl:variable name="filename" select="concat(@id,'.xml')"/> <redirect:write select="$filename"> <xsl:copy-of select="." /> </redirect:write> </xsl:template>
<xsl:template match="*" mode="x">
<xsl:if test="not(self::topic)">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:apply-templates mode="x" />
</xsl:copy>
</xsl:if>
</xsl:template><topic id="1">
<title>Root level</title>
<prolog/>
<body>
<p>This is the root-level topic.</p>
</body>
<topic id="2a">
<title>Child level 2a</title>
<prolog/>
<body>
<p>This is child level 2a.</p>
</body>
<topic id="3a">
<title>Child level 3a</title>
<prolog/>
<body>
<p>This is child level 3a.</p>
</body>
</topic>
</topic>
<topic id="2b">
<title>Child level 2b</title>
<prolog/>
<body>
<p>This is child level 2b.</p>
</body>
<topic id="3b">
<title>Child level 3b</title>
<prolog/>
<body>
<p>This is child level 3b.</p>
</body>
</topic>
<topic id="3c">
<title>Child level 3c</title>
<prolog/>
<body>
<p>This is child level 3c.</p>
</body>
</topic>
</topic>
</topic><?xml version="1.0" encoding="UTF-8"?> <topic id="1"> <title>Root level</title> <prolog/> <body> <p>This is the root-level topic.</p> </body> </topic>
<?xml version="1.0" encoding="UTF-8"?>
<topic id="2a">
<title>Child level 2a</title>
<prolog/>
<body>
<p>This is child level 2a.</p>
</body>
<topic id="3a">
<title>Child level 3a</title>
<prolog/>
<body>
<p>This is child level 3a.</p>
</body>
</topic>
</topic><?xml version="1.0" encoding="UTF-8"?>
<topic id="2b">
<title>Child level 2b</title>
<prolog/>
<body>
<p>This is child level 2b.</p>
</body>
<topic id="3b">
<title>Child level 3b</title>
<prolog/>
<body>
<p>This is child level 3b.</p>
</body>
</topic>
<topic id="3c">
<title>Child level 3c</title>
<prolog/>
<body>
<p>This is child level 3c.</p>
</body>
</topic>
</topic>-- Regards, Mukul Gandhi
Hi guys,
I'm trying to split a set of nested <topic> elements into separate XML files using the Xalan redirect extension. My input XML document could contain as many as four levels of <topic> elements, with <topic> being the root-level node. My plan is to split the root-level <topic> into its own file (without including any child <topic>s). The first level of child <topic>s would also get their own files. This set of files would include any nested <topic> elements.
My plan is to split a chapter of technical documentation containing nested topics into a separate files containing the chapter-level (overview) topic file and the major heading topics.
Can I match the two desired levels of <topic> elements using XPath? I'm guessing I could use match="root" to express the top (chapter-level) node. But I'm having some trouble wrapping my mind around the XPath processing flow ("contains"? "ancestor"? "following-sibling"?) to formulate a match for my highest child <topic> elements.
This is my input XML:
<topic id="1"> <title>Root level</title> <prolog/> <body> <p>This is the root-level topic.</p> </body> <topic id="2a"> <title>Child level 2a</title> <prolog/> <body> <p>This is child level 2a.</p> </body> <topic id="3a"> <title>Child level 3a</title> <prolog/> <body> <p>This is child level 3a.</p> </body> </topic> </topic> <topic id="2b"> <title>Child level 2b</title> <prolog/> <body> <p>This is child level 2b.</p> </body> <topic id="3b"> <title>Child level 3b</title> <prolog/> <body> <p>This is child level 3b.</p> </body> </topic> <topic id="3c"> <title>Child level 3c</title> <prolog/> <body> <p>This is child level 3c.</p> </body> </topic> </topic> </topic>
This is my desired output XML (3 separate XML files):
File 1:
<topic id="1"> <title>Root level</title> <prolog/> <body> <p>This is the root-level topic.</p> </body> </topic>
File 2:
<topic id="2a"> <title>Child level 2a</title> <prolog/> <body> <p>This is child level 2a.</p> </body> <topic id="3a"> <title>Child level 3a</title> <prolog/> <body> <p>This is child level 3a.</p> </body> </topic> </topic>
File 3:
<topic id="2b"> <title>Child level 2b</title> <prolog/> <body> <p>This is child level 2b.</p> </body> <topic id="3b"> <title>Child level 3b</title> <prolog/> <body> <p>This is child level 3b.</p> </body> </topic> <topic id="3c"> <title>Child level 3c</title> <prolog/> <body> <p>This is child level 3c.</p> </body> </topic> </topic>
This is my XSL stylesheet draft:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:redirect="http://xml.apache.org/xalan/redirect" extension-element-prefixes="redirect" version="1.0"> <xsl:output method="xml"/>
<xsl:template match="/"> <xsl:apply-templates/> </xsl:template>
<xsl:template match="root"> <xsl:variable name="filename" select="concat(@id,'.xml')"/> <redirect:write select="$filename"> <topic id="{@id}"> <xsl:apply-templates/> </topic> </redirect:write> </xsl:template>
<xsl:template match="topic[???]"> <xsl:variable name="filename" select="concat(@id,'.xml')"/> <redirect:write select="$filename"> <topic id="{@id}"> <xsl:apply-templates/> </topic> </redirect:write> </xsl:template> <xsl:template match="title"> <xsl:copy-of select="."/> </xsl:template> <xsl:template match="prolog"> <xsl:copy-of select="."/> </xsl:template> <xsl:template match="body"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet>
Any help would be greatly appreciated.
Regards, Mark
--
Mark Peters Senior Technical Writer Saba Software
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