Subject: Re: [xsl] [XSLT, Version 1] Stylesheet to embed a chunk of XML into HTML? From: "bryan rasmussen" <rasmussen.bryan@xxxxxxxxx> Date: Thu, 24 Aug 2006 14:16:49 +0200 |
<?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/"> <html> <body> <xsl:apply-templates select="//Member[1]" mode="code"/>
</body> </html> </xsl:template>
<xsl:template match="*" mode="code"> <<xsl:value-of select="name()"/> <xsl:for-each select="@*"><xsl:text> </xsl:text><xsl:value-of select="name()"/>="<xsl:value-of select="."/>"</xsl:for-each>> <xsl:apply-templates mode="code"/> </<xsl:value-of select="name()"/>> </xsl:template>
Well there is the deprecated xmp tag, other than that I think you have to pretty much escape the elements.
Cheers, Bryan Rasmussen
On 8/24/06, Costello, Roger L. <costello@xxxxxxxxx> wrote: > Hi Folks, > > I am writing a stylesheet which outputs HTML. My stylesheet pulls in a > chunk of XML from an XML file and then stuffs it within the HTML <body> > element. Here's what I want my stylesheet to generate: > > <html> > <body> > <pre> > -- XML chunk here (tags not escaped so they will display > in a browser) -- > </pre> > </body> > </html> > > When I drop the resulting HTML into a browser I want the XML chunk to > display, including the tags. > > Below is the XSLT that I thought would work, but doesn't. Can you show > me the correct way to solve this problem? > > By the way, I am not able to modify the XML file that my stylesheet > reads, so wrapping elements in the XML file within a CDATA section is > not an option for me. > > /Roger > > <?xml version="1.0"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="1.0"> > > <xsl:output method="html"/> > > <xsl:template match="/"> > <html> > <body> > <xsl:variable name="test"> > <xsl:copy-of select="//Member[1]"/> > </xsl:variable> > <pre> > <xsl:value-of disable-output-escaping="no" > select="$test"/> > </pre> > </body> > </html> > </xsl:template> > > </xsl:stylesheet>
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