Re: [xsl] xtvd grouping problem (I think)

[Steve <subsume@xxxxxxxxx>]

On 9/8/06, Bob Portnell <simply.bobp@xxxxxxxxx> wrote:
>     for each search item
>         find the set of programs which have that item
>         convert this to the set of schedule items which have those programs
>         for each in the schedule set
>             sort by time
>             report the show information.

<xsl:for-each $progSet/items[@item=@search]/@prog>
    <xsl:variable name="prog" select="@prog" />
     <xsl:for-each $scheduleSet[@prog = $prog]/@prog>
       <xsl:sort select="@time" />
       <xsl:value-of select="@showInfo"
     </xsl:for-each>
  </xsl:for-each>


> Given a variable $progSet which has a bunch of <programs> in it, how
> do I define a $schedSet which has only <schedule> items containing
> @program ids from $progSet?
>
> I've gotten as far as
> <xsl:variable name="schedSet" select="//schedule[@program . . {sound
> of screeching brakes}? />

Pretty sure I touched on this above. Let me know.

> Please excuse where I've strayed from proper XSLT vocabulary; I hope
> my intent is clear enough despite such lapses of inexperience.

No problemo. Was very well conveyed. =).

-S