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Subject: Re: [xsl] XML Question From: LINKE Markus <markus.linke@xxxxxxxx> Date: Tue, 3 Oct 2006 16:47:02 -0500 (CDT) |
I've tried it but I receive an:
SystemID: xxx.xsl
Location: 98:0
Description: The URI urn:schemas-microsoft-com:xslt does not identify an external Java class
error message at this location:
</xsl:variable>
<xsl:value-of select="msxsl:node-set($theResult)"/> <!-- here -->
</xsl:template>
???
Thanks for your help!
Markus
----- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> You need to apply this code:
> http://www.topxml.com/code/default.asp?p=3&id=v20010323001030
>
> to all leaf nodes in the tree.
>
>
>
> --
> Cheers,
> Dimitre Novatchev
> ---------------------------------------
> Truly great madness cannot be achieved without significant
> intelligence.
> ---------------------------------------
> To invent, you need a good imagination and a pile of junk
> -------------------------------------
> You've achieved success in your field when you don't know whether
> what
> you're doing is work or play
>
>
>
> On 10/3/06, LINKE Markus <markus.linke@xxxxxxxx> wrote:
> > this might be the better audience ...
> >
> > ----- LINKE Markus <markus.linke@xxxxxxxx> wrote:
> > > Hi,
> > >
> > > I am not sure if this is the right list for such a question, but
> lets
> > > try :)
> > >
> > > I would like to create a list of xpaths via xsl from a given
> > > xml-structure like this:
> > >
> > > <a>
> > > <b>
> > > <c>
> > > content
> > > </c>
> > > <d>
> > > morecontent
> > > </d>
> > > </b>
> > > </a>
> > >
> > > it should show the full xpath like
> > >
> > > a/b/c ====> content
> > > a/b/d ====> morecontent
> > >
> > > and not just
> > >
> > > c => content
> > > d => morecontent
> > >
> > > Ideas anyone? I am looking for either a script or some xsl ...
> > >
> > > Cheers,
> > > Markus
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