Subject: Re: [xsl] XSLT1.0 xml-stylesheet into XML output From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Fri, 20 Oct 2006 12:47:23 +0100 |
Hello,
I'm having the following:
XSL:
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="UTF-8" doctype-public="-//W3C//DTD HTML 4.01 Transitional//EN" indent="no"/>
<!-- root --> <xsl:template match="/"> <!-- Inv Part --> <Inv> <Acc> <Name>ABCDEF</Name> <FamName>XYZ</FamName> </Acc> </Inv> </xsl:template> </xsl:stylesheet>
Generated by this XSL XML:
<?xml version="1.0" encoding="UTF-8"?> <Inv> <Acc> <Name>ABCDEF</Name> <FamName>XYZ</FamName> </Acc> </Inv>
But I want to have the following XML as output:
<?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xml" href="Name.xsl"?> <Inv> <Acc> <Name>ABCDEF</Name> <FamName>XYZ</FamName> </Acc> </Inv>
What changes into XSL is needed?
cheers andrew
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