Subject: Re: [xsl] top ancestor value From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Fri, 20 Oct 2006 14:58:03 -0700 |
To learn XPath by just having fun I'm usually recommending the XPath Visualizer :o)
-- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play
I've been searching on this and I can't find an example that helps. I find the generic examples but I don't get something that does what I want.
My data is structured so that only the top level of the tree has the folder for the url. but I want to include that folder in the url for all of the files (including itself). Based on stuff I've read I thought that would be "ancestor-or-self::section[last()]/folder," but that gives me nothing. (full xsl below)
I tried using youth:ancestor-or-self::section[last()]/folder, but that gives me a validation error. The data is here: http://rafb.net/paste/results/dyNo4Q36.html for reference
Am I completely misunderstanding ancestor? And in general, how does one debug this kind of thing?
Thanks again Joelle
I've got this: <?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:youth="http://www.youthhood.org" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/"> <html> <body> <h2>My Sitemap</h2> <ul> <xsl:for-each select="youth:sitemap//youth:section"> <li><xsl:value-of select="youth:id" />: <a> <xsl:attribute name="href"> <xsl:value-of select="concat('../', ancestor-or-self::section[last()]/folder,'/', youth:url)"/> </xsl:attribute> <xsl:value-of select="youth:title" /></a></li> </xsl:for-each> </ul> </body> </html> </xsl:template> </xsl:stylesheet>
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