Subject: Re: [xsl] Getting ordering info from a lookup table From: Nic James Ferrier <nferrier@xxxxxxxxxxxxxxxxxxxx> Date: Mon, 30 Oct 2006 23:53:14 +0000 |
"Trevor Nicholls" <trevor@xxxxxxxxxxxxxxxxxx> writes: > My transform is using an external XML file as a lookup table. Among other > things, the external file contains a list: > ... > <files> > <doc>file_one</doc> > <doc>file_two></doc> > <doc>file_three</doc> > ... > </files> > > Each time the transform runs, the input XML file corresponds to one of the > <doc> elements in the lookup file. The input file name is passed in as a > parameter to the transformation. > > <xsl:param name="myself" /> > > I think the following construction can do the lookup to the external file > and locate the current doc: > > .. select="document('lookup.xml')/files/doc[. = $myself]" > > but of course this is pointless by itself as I already have the doc name. > What I actually want is to obtain the names of the previous and next docs - > if they exist. There's surely an elegant way to do this, but I don't know > it. What can I do? How about: select="document('lookup.xml')/files/doc[. = $myself]"/preceding-sibling::." and of course: select="document('lookup.xml')/files/doc[. = $myself]"/following-sibling::." -- Nic Ferrier http://www.tapsellferrier.co.uk for all your tapsell ferrier needs
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