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Subject: Re: [xsl] Grouping using concatenated key From: jmcreynolds@xxxxxxxxxxxxxx Date: Mon, 11 Dec 2006 10:36:21 -0600 (CST) |
David,
Thanks again for your help. It does help if the person seeking help
follows the rules, no? :) Sorry for not adhering to the guidelines of the
group...
Here is the abbreviated XML representation that I am working with:
<NewDataset>
<BillDetail>
<OBLIGATION_ID>2750</OBLIGATION_ID>
<PHONE_NUMBER>1234567890</PHONE_NUMBER>
</BillDetail>
<BillDetail>
<OBLIGATION_ID>2750</OBLIGATION_ID>
<PHONE_NUMBER>9876543210</PHONE_NUMBER>
</BillDetail>
<BillDetail>
<OBLIGATION_ID>3940</OBLIGATION_ID>
<PHONE_NUMBER>1234567890</PHONE_NUMBER>
</BillDetail>
</NewDataset>
Does this clarify things?
Many thanks (yet again!),
JOHN
>
> <xsl:template match="/">
>
> so you are at the document root. in a well formed document there can
> only be exactly one element child of / so
>
> <xsl:for-each
> select="BillDetail[
>
> you are for-eaching over at one element so grouping is not going to be
> very interesting.
>
> i suspect that you have multiple BillDetail elements and they have a
> parent element, in which case you should (or could) put the grouping
> code in the template for that element.
>
> Please see the posting guidelines at the list home page, which suggests
> posting _complete_ _small_ examples. Your posted input was quite large
> but has lots of detail not relevant to the problem (<FROM_CITY> and
> friends) but isn't a well formed document as the two elements have no
> parent element so peopel can't post code that actually runs on your
> example.
>
> David
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