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Subject: [xsl] Dynamic Menu Using XSL From: Brant Schroeder <brantschr@xxxxxxxxx> Date: Mon, 11 Dec 2006 10:01:25 -0800 (PST) |
I am trying to create a dynamic menu using XML and XSLT. Here is my XML
<?xml version="1.0" encoding="iso-8859-1" ?>
<?xml-stylesheet type="text/xsl"
href="mymenu.xsl"?>
<menu>
<item id = "1" url="default.aspx"
title="Home"></item>
<item id = "2" url="default.aspx?id=Training"
title="Training">
<item id = "3" url="default.aspx?id=Search_Training"
title="Search Training"></item>
<item id = "4"
url="default.aspx?id=Post_Training" title="Post Training"></item>
</item>
<item id = "7" url="default.aspx?id=Other_Training"
title="Other Training">
<item id = "8"
url="default.aspx?id=Search_Other_Training" title="Search Other
Training"></item>
<item id = "9"
url="default.aspx?id=Post_Other_Training" title="Post Other Training"></item>
</item>
<item id = "11" url="default.aspx?id=About_Us" title="About
Us">
<item id = "12" url="default.aspx?id=Location" title="Location">
<item id = "13" url="default.aspx?id=Map" title="View Map"></item>
</item>
</item>
</menu>I am using the following XSLT to generate my HTML
<?xml version="1.0" encoding="utf-8"?>
<xsl:param name="URL"/>
<xsl:output indent="yes"/>
<xsl:template match="menu">
<html>
<body>
<ul>
<xsl:apply-templates/>
</ul>
</body>
</html>
</xsl:template>
<xsl:template match="item">
<li>
<a href="{@url}">
<xsl:value-of select="@title"/>
</a>
<xsl:if test="item">
<ul>
<xsl:apply-templates/>
</ul>
</xsl:if>
</li>
</xsl:template>
</xsl:stylesheet>
I would
like to hide the child menu if the parent menu is not selected. I would also
like the parent menu to be expanded if a child menu is selected. I am passing
the url as a parameter (ex: default.aspx, default.aspx?id=About_us) this
matches the URL attribute of the item. I am new to XSLLT and would
appreciate any help.
Thanks
Brant
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