Re: [xsl] Only output element when parameter value is not equal to blank (or null)

[Abel Braaksma <abel.online@xxxxxxxxx>]

Hi Chris,

You can make your stylesheet miles simpler and shorter by using a 
different approach. Instead of tons of parameters, use something 
extensible, like an XML structure (why not, it's all xml anyway). You 
can then do it the 'xslt way' by defining templates. You code can become 
this:

<xsl:param name="key-settings">
   <setting name="MASTERCATALOGNAME" value="myvalue" />
   <setting name="PRODUCTID" value="myprodid" />
   ....
</xsl:param>

<xsl:template match="/" >

 <DataService>
    <Identity>
  [...]
    </Identity>
    <Transaction>
       <Command type="Query">
          <MasterCatalogRecord etype="Entity">
              <ExternalKeys>
                  <xsl:apply-template select="$key-settings/setting" />
              </ExternalKeys>
      [...]
    </Transaction>
 </DataService>

</xsl:template>

<xsl:template match="setting">
   <Key name="{@name}" type="string">
      <xsl:value-of select="@value" />
   </Key>
</xsl:template>



That's all there is too it. There is no need to add any xsl:if anymore, 
as the processor will do the thinking for you. If you don't want to 
chain the name of the Key to the name of the Setting, you can choose to 
add an external source that contains a lookup table (also in XML) with 
all your paramname/keyname mappings. You can get this resource with 
doc() or document() function.

If you use XSLT 1, you must use the node-set() extension function.

Cheers!

-- Abel Braaksma